write pseudocode that will inform youtuber the number of "Like"(L) based on 1000 viewer
Fthh
Here is one way to write the pseudocode for this task:
START
SET number_of_viewers = 1000
SET number_of_likes = 0
FOR i = 1 TO number_of_viewers
IF viewer[i] liked the video
number_of_likes = number_of_likes + 1
END IF
END FOR
PRINT number_of_likes
END
This pseudocode uses a loop to iterate over each viewer and check whether they liked the video. If they did, it increments the number_of_likes variable by 1. At the end, it prints the final value of number_of_likes.
This is just one way to write the pseudocode, and there are many other ways you could achieve the same result. The important thing is to communicate the steps you are taking in a clear and concise way, using the conventions of pseudocode.
To write a pseudocode that informs a YouTuber about the number of likes based on 1000 viewers, you can follow these steps:
1. Input the total number of viewers (V).
2. Set the constant variable "conversion_rate" to 1000.
3. Calculate the number of likes (L) by dividing the total number of viewers (V) by the conversion rate (1000).
4. Output the number of likes (L) to the YouTuber.
Here's the pseudocode:
```
Input V // total number of viewers
Set conversion_rate = 1000 // constant conversion rate
L = V / conversion_rate // calculate the number of likes
Output "Number of Likes: " + L // display the number of likes to the YouTuber
```
Note: The above pseudocode assumes that the conversion rate remains constant at 1000 likes per 1000 viewers. In reality, the number of likes can vary based on various factors, including the content of the video and viewer preferences.