Calculate the concentration of the nitrate ion in a solution made by mixing 45.0 mL of 1.50 M silver nitrate solution with 50.0 mL of 4.10 M calcium nitrate solution.
molsAgNO3 = M x L =mols NO3^-
mols Ca(NO3)2 = M x L and that x 2 = mols NO3^-
Then total mols NO3^-/total volume in L = M of the nitrate ion
To calculate the concentration of the nitrate ion in the resulting solution, we need to apply the principle of conservation of moles.
First, let's determine the moles of nitrate ions in each solution.
For the silver nitrate solution:
Molarity (M) = moles/Liter
Moles = Molarity × Volume (in Liters)
Moles of nitrate ions in silver nitrate solution = 1.50 M × 0.045 L
For the calcium nitrate solution:
Moles of nitrate ions in calcium nitrate solution = 4.10 M × 0.050 L
Since nitrate ions do not undergo any chemical reaction upon mixing, the total moles of nitrate ions in the resulting solution will be the sum of the moles from each solution.
Total moles of nitrate ions = Moles of nitrate ions in silver nitrate solution + Moles of nitrate ions in calcium nitrate solution
Now, let's calculate the total moles of nitrate ions:
Total moles of nitrate ions = (1.50 M × 0.045 L) + (4.10 M × 0.050 L)
Once we have the total moles of nitrate ions, we can calculate the concentration of the nitrate ion in the resulting solution.
Concentration (M) = Moles of nitrate ions / Total volume (in Liters)
Total volume = Volume of silver nitrate solution + Volume of calcium nitrate solution
Total volume = 45.0 mL + 50.0 mL = 95.0 mL = 0.095 L
Now, let's calculate the concentration of the nitrate ions:
Concentration = Total moles of nitrate ions / Total volume
Concentration = (1.50 M × 0.045 L + 4.10 M × 0.050 L) / 0.095 L
Simplify and calculate the result to find the concentration of the nitrate ion in the resulting solution.
To calculate the concentration of the nitrate ion in the mixture, we first need to determine the moles of nitrate ions present in each solution. Then, we can add up the moles from both solutions and calculate the concentration.
Let's start by calculating the moles of nitrate ion in the silver nitrate solution:
Moles of nitrate ion in silver nitrate solution = volume of solution (L) × molarity of nitrate ion (mol/L)
Since the molarity of silver nitrate is 1.50 M and the volume is given as 45.0 mL (or 0.045 L):
Moles of nitrate ion in silver nitrate solution = 0.045 L × 1.50 mol/L
Next, let's calculate the moles of nitrate ion in the calcium nitrate solution:
Moles of nitrate ion in calcium nitrate solution = volume of solution (L) × molarity of nitrate ion (mol/L)
The molarity of calcium nitrate is given as 4.10 M, and the volume is given as 50.0 mL (or 0.050 L):
Moles of nitrate ion in calcium nitrate solution = 0.050 L × 4.10 mol/L
Now, we can add up the moles of nitrate ions from both solutions:
Total moles of nitrate ion = moles from silver nitrate solution + moles from calcium nitrate solution
Total moles of nitrate ion = (0.045 L × 1.50 mol/L) + (0.050 L × 4.10 mol/L)
Finally, we can calculate the concentration of the nitrate ion in the mixture by dividing the total moles of nitrate ion by the total volume of the solution.
Concentration of nitrate ion = Total moles of nitrate ion / Total volume of solution
Total volume of solution = volume of silver nitrate solution + volume of calcium nitrate solution
Total volume of solution = 0.045 L + 0.050 L
Now, we have all the information needed to calculate the concentration of the nitrate ion in the solution made by mixing the two solutions.