A disk of a radius 50 cm rotates at a constant rate of 100 rpm. What distance in meters will a point on the outside rim travel during 30 seconds of rotation?
Is this correct
R= 50 cm=0.5 m f=100 rpm
W=2pif=2pi(100)=200pi rad/min=200pi (rad/60s)=10/3pi rad/s
Theta=wt=10/3pi(30)=100pi rad or 314 rad
S=r(theta)=(0.5)(100pi)=50pi m Or 157 m
circumference = 2 pi r = 2 * 3.14 * 0.5 = 3.14 meters
100* 3.14 meters / 60 seconds
half of that in 30 seconds
50 * 3.14 /60 = 2.62 meters