The compound shown will give clues to its structure by which of the following spectral features ? (Assume there is no magnetic coupling with the aldehyde proton.)
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A strong , broad absorption at about 3300 wavenumbers (IR)
A strong , sharp absorption at about 1730 wavenumbers (IR) (True)
A triplet at about delta = 6.8 ppm , integrating for 2 protons (NMR)
A sharp singlet in the region of delta = 3.5 ppm (NMR)
An important pair of moderately strong absorptions at about 800 and 900 wavenumbers (IR)
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Well, well, well, let's take a look at this compound and its spectral features. You might want to make sure you have your sense of humor ready for this one!
Now, the compound in question gives us some clues about its structure through its spectral features. We have a strong, broad absorption at about 3300 wavenumbers in the infrared (IR) spectrum. Well, it seems like this compound is so excited to have its structure revealed that it's doing a little dance, a broad absorption dance!
Next up, we have a strong, sharp absorption at about 1730 wavenumbers in the IR spectrum. Oh, look at that! This compound is showcasing its sharp moves with a strong absorption at 1730 wavenumbers. Impressive!
Moving on to the NMR spectrum, we have a triplet at about delta = 6.8 ppm, integrating for 2 protons. It seems like these protons are really in sync, forming a triplet dance group at 6.8 ppm. Their moves are so coordinated, they should consider joining a synchronized swimming team!
And finally, we have a sharp singlet in the region of delta = 3.5 ppm in the NMR spectrum. This singlet is so sharp, it could be a professional circus knife thrower! Watch out, folks!
Ah, but we're not done yet! We also have a pair of moderately strong absorptions at about 800 and 900 wavenumbers in the IR spectrum. These absorptions are like a dynamic duo, joining forces to give us important clues about the compound's structure. They're like Batman and Robin, the spectral superheroes!
So, after all that humor, the correct answer would be: A strong, sharp absorption at about 1730 wavenumbers (IR), and An important pair of moderately strong absorptions at about 800 and 900 wavenumbers (IR).
I hope I brought a smile to your face while helping you with your question! Feel free to dance your way to the next one!
The compound shown will give clues to its structure through the following spectral features:
1. A strong, broad absorption at about 3300 wavenumbers (IR)
2. A strong, sharp absorption at about 1730 wavenumbers (IR)
3. A triplet at about delta = 6.8 ppm, integrating for 2 protons (NMR)
4. A sharp singlet in the region of delta = 3.5 ppm (NMR)
5. An important pair of moderately strong absorptions at about 800 and 900 wavenumbers (IR)
From the given options, the correct answer is:
A strong, sharp absorption at about 1730 wavenumbers (IR)
To determine the answer to this question, we need to analyze the given spectral features and understand their significance in providing clues about the structure of the compound.
First, let's analyze the infrared (IR) spectrum:
- A strong, broad absorption at about 3300 wavenumbers (IR) indicates the presence of an O-H bond, typically found in alcohols or carboxylic acids. However, this compound does not have any such absorption, so it is not relevant to the structure determination in this case.
- A strong, sharp absorption at about 1730 wavenumbers (IR) is commonly associated with the presence of a C=O (carbonyl) functional group. This suggests that the compound contains an aldehyde group, which is a carbonyl group bonded to at least one hydrogen atom. This clue is relevant to determining the structure.
Next, let's analyze the nuclear magnetic resonance (NMR) spectrum:
- A triplet at about delta = 6.8 ppm, integrating for 2 protons (NMR), indicates the presence of a CH2 group. The splitting pattern and integration suggest that these protons are adjacent to a CH group. However, this information is not directly related to the structure determination.
- A sharp singlet in the region of delta = 3.5 ppm (NMR) typically corresponds to a group containing CH3 or CH2 protons. This suggests the presence of a methyl or methylene group, but it does not provide specific details about the structure.
Based on this analysis, the relevant spectral feature that gives clues to the structure of the compound is the strong, sharp absorption at about 1730 wavenumbers in the infrared spectrum (IR). This indicates the presence of an aldehyde group (C=O), which can be used to narrow down the possible structure options.