A spring stretches by 6cm when supporting a load of 15N ,what load would make the spring extend by 25mm
I am asking the same
Yeah wat
I am asking the same
6cm=15N
2.5cm=?
2.5cm*15N/6cm
ans=6.25N
This answer is incorrect.
To solve this problem, we can use the equation:
F = kx
where F is the force applied to the spring, x is the displacement of the spring from its resting position, and k is the spring constant.
We can rearrange this equation to solve for k:
k = F/x
We know that when the spring is supporting a load of 15N, it stretches by 6cm. So we can plug these values into the equation:
k = 15N / 0.06m = 250 N/m
Now we can use this value of k to find the force required to extend the spring by 25mm:
F = kx = (250 N/m) * 0.025m = 6.25N
Therefore, a load of 6.25N would make the spring extend by 25mm.
To find the load that would make the spring extend by 25mm, we can use Hooke's Law, which states that the force exerted by a spring is proportional to the displacement it undergoes.
Hooke's Law can be written as:
F = k * x
Where:
F is the force exerted by the spring (load)
k is the spring constant (a measure of stiffness of the spring)
x is the displacement of the spring
To find the spring constant, we need to use the information given in the problem. We know that the spring stretches by 6cm (which is equivalent to 0.06m) when supporting a load of 15N.
Therefore, we can rearrange Hooke's Law and solve for k:
k = F / x
k = 15N / 0.06m
k = 250 N/m
Now that we have the spring constant, we can find the load (F) that would make the spring extend by 25mm (which is equivalent to 0.025m).
Using Hooke's Law, we can substitute the values we have:
F = k * x
F = 250 N/m * 0.025m
F = 6.25 N
Therefore, a load of 6.25N would make the spring extend by 25mm.