A heavy box is pulled across a qooden floor with a rope. the rope makes an angle of 60⁰ with the floor. A force of 75N is exerted on the rope.
To determine the components of the force acting on the box, we can break down the force into its horizontal and vertical components.
The force exerted on the rope is 75N, and it makes an angle of 60 degrees with the floor. We can use trigonometry to find the horizontal and vertical components.
First, let's find the vertical component of the force. We can use the sine function:
Vertical component = Force * sin(angle)
= 75N * sin(60 degrees)
= 75N * 0.866 (rounded to 3 decimal places)
= 64.95N
So, the vertical component of the force is approximately 64.95N.
Next, let's find the horizontal component of the force. We can use the cosine function:
Horizontal component = Force * cos(angle)
= 75N * cos(60 degrees)
= 75N * 0.5
= 37.5N
So, the horizontal component of the force is 37.5N.
Therefore, when a force of 75N is exerted on the rope at an angle of 60 degrees with the floor, there will be a vertical component of approximately 64.95N and a horizontal component of 37.5N acting on the heavy box.