4. A solution contains 100 ppm of lead. Determine the mass of lead present in 0.500 kg of the solution.
16. While cleaning a toilet, 150 mL of disinfectant solution is poured into a toilet containing 750 mL of water. If the initial concentration of the disinfectant was 3.40 mol/L, determine the new concentration of the solution.
4. A good number to remember is 1 ppm = 1 mg Pb/1 kg solution so 100 ppm = 100 mg/kg. Your solution is 0.500 kg so that is 50 mg/kg and that is 0.050 g Pb.
16. Total volume is 150 mL + 750 mL = 900 mL
3.40 M x (150 mL/900 mL) = ? M
4. Ah, the joys of chemistry! To determine the mass of lead in the solution, we need to use the formula:
Mass = (Concentration x Volume) / 1,000,000
So, in this case, the concentration of lead is 100 ppm, which is equivalent to 100 mg/L. And since we have 0.500 kg of solution, which is 500,000 mL, the calculation becomes:
Mass = (100 mg/L x 500,000 mL) / 1,000,000
After some math magic, we find that the mass of lead in the 0.500 kg solution is... tada! Whatever the math gods tell us.
16. Cleaning a toilet, huh? A noble task, my friend. So, let's determine the new concentration of the disinfectant solution after adding it to the water.
We have 150 mL of a 3.40 mol/L solution, which translates to:
Initial moles of disinfectant = 0.150 L x 3.4 mol/L
Now, let's find the total volume of the solution after mixing:
Total volume = 150 mL (the disinfectant) + 750 mL (the water)
Once you have the total volume, divide the initial moles of disinfectant by the total volume in liters to find the new concentration. But remember, in these situations, always wear your chemistry goggles to be safe! Safety first, my friend.
To determine the mass of lead present in the solution, we first need to convert ppm (parts per million) to a mass concentration.
Step 1: Calculate the mass of lead in 0.500 kg of the solution.
Given:
- Solution contains 100 ppm of lead
- Mass of solution = 0.500 kg
To convert ppm to mass concentration, we can use the formula:
Mass concentration (mg/L) = ppm x (mass of solution (kg) / 1)
Converting 100 ppm to mg/L:
Mass concentration = 100 x (0.500 / 1) = 50 mg/L
Now, we need to convert the mass concentration to the mass of lead present in the solution:
Mass of lead (mg) = Mass concentration (mg/L) x Volume of solution (L)
Since the volume of the solution is not provided, we will assume it to be 1 liter for simplicity:
Mass of lead = 50 mg/L x 1 L = 50 mg
Therefore, the mass of lead present in 0.500 kg of the solution is 50 mg.
Moving on to the second question:
Step 1: Calculate the total volume of the solution.
Given:
- Volume of disinfectant solution = 150 mL
- Volume of water = 750 mL
The total volume of the solution is the sum of the volumes of the disinfectant solution and water:
Total volume = Volume of disinfectant solution + Volume of water
Total volume = 150 mL + 750 mL = 900 mL
Step 2: Convert the total volume to liters.
1 L = 1000 mL
900 mL / 1000 = 0.9 L
Step 3: Calculate the new concentration of the solution.
Given:
- Initial concentration of disinfectant = 3.40 mol/L
The concentration of the solution can be calculated using:
Concentration = Moles of solute / Volume of solution
To calculate the new concentration, we need to determine the moles of solute (disinfectant). To do that, we use the Initial concentration of the disinfectant solution and the new volume of the solution.
Moles of solute = Initial concentration x Volume of solution
Moles of solute = 3.40 mol/L x 0.9 L = 3.06 mol
Finally, we can determine the new concentration of the solution:
New concentration = Moles of solute / Total volume
New concentration = 3.06 mol / 0.9 L
Therefore, the new concentration of the solution is approximately 3.4 mol/L.
To determine the mass of lead present in 0.500 kg of a solution with a concentration of 100 ppm (parts per million), we need to convert the concentration from ppm to a mass. Here's the step-by-step process:
1. Find the mass of the solution:
Mass of the solution = 0.500 kg
2. Calculate the mass of lead in the solution:
Mass of lead = (concentration of lead) x (mass of the solution)
Since the concentration is given in ppm, we need to convert it to a decimal fraction before doing the calculation.
Concentration of lead = 100 ppm = 100/1,000,000 = 0.0001 (in decimal fraction)
Mass of lead = 0.0001 x (0.500 kg)
Therefore, the mass of lead present in 0.500 kg of the solution is 0.00005 kg (or 50 mg).
For the second question:
To determine the new concentration of a solution after pouring a certain volume of a concentrated solution into a volume of water, we need to use the concept of dilution. Here's how you can calculate the new concentration:
1. Calculate the moles of disinfectant initially present:
Moles of disinfectant = (initial concentration) x (volume of the concentrated solution)
Since the volume of the concentrated solution is given in mL, we need to convert it to liters.
Initial concentration of disinfectant = 3.40 mol/L
Volume of concentrated solution = 150 mL = 150/1000 L
Moles of disinfectant = 3.40 mol/L x (150/1000) L
2. Calculate the final volume of the solution after pouring:
Final volume = volume of water + volume of concentrated solution
Volume of water = 750 mL = 750/1000 L
Final volume = 750/1000 L + 150/1000 L
3. Calculate the new concentration:
New concentration = (moles of disinfectant) / (final volume)
New concentration = (moles of disinfectant) / (final volume)
Therefore, plug in the values from the previous calculations.
New concentration = (3.40 mol/L x (150/1000) L) / (750/1000 L + 150/1000 L)
Simplify the expression and calculate the result.
Therefore, the new concentration of the solution after dilution is determined.