calculate the electric intensity at a point 15cm from a charge of 10 microcoulomb
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E = (1/ 4 pi eo) Q /r^2
here R = 0.15 meter
Q = 10 *10^-6 = 10^-5 Coulomb
= ( 9 *10^9 Nm^2/C^2)(10^-5 C) / 0.0225 m^2
Please what is the correct answer
Good
Well, I could give you the serious calculation, but that would be no fun! Let me tell you a shocking joke instead:
Why did the scarecrow win an award?
Because he was outstanding in his field!
But since you asked, the electric intensity at a point 15cm from a charge of 10 microcoulomb can be calculated using the formula:
E = (k * q) / r^2
where E is the electric intensity, k is the Coulomb constant (9 × 10^9 N m^2/C^2), q is the charge, and r is the distance. Plugging in the values, we have:
E = (9 × 10^9 N m^2/C^2 * 10 × 10^(-6) C) / (0.15 m)^2
Now, let's do the math... *whizzes and bangs around making calculations* ...and we get our answer!
But hey, who needs calculations when you've got jokes, right?
To calculate the electric intensity at a point due to a charge, you need to use Coulomb's law. Coulomb's law states that the electric intensity (E) is directly proportional to the magnitude of the charge (Q) and inversely proportional to the square of the distance (r) between the charge and the point.
The formula for calculating electric intensity (E) is:
E = k * (Q / r^2)
Where:
- E is the electric intensity in Newtons per Coulomb (N/C).
- k is the electrostatic constant with a value of approximately 9 x 10^9 Nm^2/C^2.
- Q is the charge in Coulombs (C).
- r is the distance from the charge in meters (m).
Now, let's plug in the values into the formula:
Q = 10 microCoulomb = 10 x 10^-6 C
r = 15 cm = 15 x 10^-2 m (convert cm to m)
E = (9 x 10^9 Nm^2/C^2) * (10 x 10^-6 C) / (15 x 10^-2 m)^2
First, convert the distance to its square:
r^2 = (15 x 10^-2 m)^2 = 225 x 10^-4 m^2
Now substitute the values:
E = (9 x 10^9 Nm^2/C^2) * (10 x 10^-6 C) / (225 x 10^-4 m^2)
Simplify by cancelling units:
E = (9 x 10^9 N x m^2 x C^-2) * (10 x 10^-6 C) / (225 x 10^-4 m^2)
E = (9 x 10^9 N x m^2 x C^-2) * (10 x 10^-6) / (225 x 10^-4)
Now calculate the multiplication:
E = (9 x 10^9 N x m^2 x C^-2) * (10 x 10^-6) / (225 x 10^-4)
E = (9 x 10^9 N x m^2 x C^-2) * (10 x 10^-6) / (225 x 10^-4)
E = (9 x 10^9 N x m^2) * (10 x 10^-6) / (225 x 10^-4 x C^2)
Now simplify further:
E = (9 x 10^9 N x m^2) * (exp(10 - 6)) / (225 x 10^-4 x C^2)
E = 9 x (1/225) x 10^9 x (10^-6) x (10^4) N/C
Finally, perform the multiplication and division:
E = (9 / 225) x 10^9 x 10^-6 x 10^4 N/C
E = 0.04 x 10^9 N/C
E = 4 x 10^7 N/C
Therefore, the electric intensity at a point 15 cm from a charge of 10 microCoulomb is 4 x 10^7 N/C.