Ted and Sam have new bikes and already Ted has ridden 8 miles. Sam has ridden 1 mile. If each one rides 1 mile a day, how many days will it be before Ted has ridden twice as far as Sam?

6 answers

8+x = 2(1+x)

8 - 1 - 1 = 6

So easy

6

8+x = 2 + 2 x

6 = x

I have no idea what you did gtif

Or

1 + 1 = 2

8 - 2 = 6

To solve this problem, we need to determine how many miles each person needs to ride in order for Ted to have ridden twice as far as Sam.

Let's assume it will take "x" days for this to happen.

We know that Ted has already ridden 8 miles and Sam has ridden 1 mile.

Since they each ride 1 mile per day, Ted's total distance after "x" days is 8 + x, and Sam's total distance after "x" days is 1 + x.

According to the problem, Ted needs to have ridden twice as far as Sam after "x" days.

So, we can set up the following equation:

8 + x = 2(1 + x)

Now, let's solve this equation to find the value of "x":

8 + x = 2 + 2x
8 - 2 = 2x - x
6 = x

Therefore, it will take 6 days for Ted to have ridden twice as far as Sam.