A vial in a chemistry lab had a label "2.79 mol CaCl2". How many grams of CaCl2 are there in that vial?
right
grams = mols x molar mass = ?
@DrBob222..
so it would be 2.79 x 110.98?
To determine the number of grams of CaCl2 in the vial, you need to use the molar mass of CaCl2 and the given number of moles.
The molar mass of CaCl2 can be calculated by adding the atomic masses of calcium (Ca) and chlorine (Cl):
Molar mass of CaCl2 = (atomic mass of Ca) + 2 × (atomic mass of Cl)
Looking up the atomic masses:
Atomic mass of Ca = 40.08 g/mol
Atomic mass of Cl = 35.45 g/mol
Plugging in the values:
Molar mass of CaCl2 = 40.08 g/mol + 2 × 35.45 g/mol
Molar mass of CaCl2 = 40.08 g/mol + 70.90 g/mol
Molar mass of CaCl2 = 110.98 g/mol
Now that we know the molar mass of CaCl2 is 110.98 g/mol, we can use the given number of moles (2.79 mol) to calculate the grams of CaCl2:
Grams of CaCl2 = (number of moles) × (molar mass of CaCl2)
Grams of CaCl2 = 2.79 mol × 110.98 g/mol
Grams of CaCl2 = 309.0542 g
Therefore, there are approximately 309.05 grams of CaCl2 in the vial labeled "2.79 mol CaCl2."