PLEASE HELP! Use your calculator to find the length of the arc from t = 0 to t = 3 of x = 2t + 1, y = t2 - 1.
Type your answer in the space below and give 3 decimal places. If your answer is less than 1, place a leading "0" before the decimal point (ex: 0.482). (15 points)
it would be nice if you would read the answers already given ...
s = ∫[0,3] √((2)^2 + (2t)^2) dt
= ∫[0,3] 2√(1 + t^2) dt
this is a standard form, so finish it off.