Find the velocity vector for a particle whose position vector is (2t, 5) for all t. (15 points)
A) (2, 0)
B) (t^2, 5t)
C) (t^3/3 , 5t^2/2)
D) square root of 4t^2 + 25
d/dt 2t = 2
d/dt 5 = 0
A) (2, 0)
B) (t^2, 5t)
C) (t^3/3 , 5t^2/2)
D) square root of 4t^2 + 25
d/dt 5 = 0