A brick is initially at rest on top of a rough horizontal surface, as shown in the diagram. The brick is pushed by a force F=25N parallel to the surface and starts to move. The weight of the brick 𝑊=28N.What must the coefficient of static friction of the brick with the surface be less than?
A brick is initially at rest on top of a rough horizontal surface, as shown in the diagram. The brick is pushed by a force F=22N parallel to the surface and starts to move. The coefficient of static friction of the brick with the surface is 0.75. What must the weight of the brick, be less than?
A brick is initially at rest on top of a rough horizontal surface, as shown in the diagram. The brick is pushed by a force F parallel to the surface. The weight of the brick W=30 N.
The coefficient of static friction of the brick with the surface is 0.75. What must the magnitude of F exceed to start the brick moving across the surface?
so, you've taken the time to post the same thing three times.
Have you actually done any work on it yet?
You only have a few numbers to work with, and clearly at this point, you have only learned a few formulas and rules for motion. So, any problem assigned will use one of those few rules. So review the topic and post your work on attempting to solve the problem. "I am clueless" just means you haven't bothered to study yet.
To determine the coefficient of static friction required for the brick to start moving, we need to consider the forces acting on the brick.
When the brick is at rest, there are two main forces acting on it:
1. The force of gravity or weight (W) acting vertically downward.
2. The normal force (N) exerted by the surface, which is perpendicular to the surface.
Since the brick is initially at rest, the static friction force (Fs) must be equal in magnitude and opposite in direction to the applied force (F) in order to maintain equilibrium. The static friction force can be calculated as:
Fs = μs * N
Where μs is the coefficient of static friction.
In this case, the applied force is F = 25 N, and the weight of the brick is W = 28 N. The normal force (N) is equal to the weight (N = W) since the brick is on a horizontal surface.
To determine the maximum value of μs that allows the brick to start moving, we need to find the maximum value of static friction. This occurs when Fs is at its maximum value, known as the limiting static friction (Fs(max)).
Fs(max) = μs(max) * N
Setting Fs = Fs(max), we can solve for the maximum coefficient of static friction:
μs(max) = Fs(max) / N
Substituting the values, we get:
μs(max) = F / N = 25 N / 28 N = 0.89
Therefore, the coefficient of static friction (μs) must be less than 0.89 for the brick to start moving.