The specific heat capacity of zinc is 0.386 J/g ºC . How many joules would be released when 268 grams of zinc at 96.0 ºC were cooled to 28.0 ºC?
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To find the amount of energy released, we can use the formula Q = mcΔT, where Q is the heat energy exchanged, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature.
First, we need to calculate the change in temperature, which is given by ΔT = T2 - T1, where T2 is the final temperature and T1 is the initial temperature.
ΔT = 28.0 ºC - 96.0 ºC
ΔT = -68.0 ºC
Next, we can calculate the amount of energy released using the formula Q = mcΔT:
Q = (268 g)(0.386 J/g ºC)(-68.0 ºC)
When we multiply these values together, we get the energy released:
Q ≈ -7114.208 J
So approximately 7114.208 joules of energy would be released when 268 grams of zinc at 96.0 ºC were cooled to 28.0 ºC.