Write an equation in standard form of the circle with the given properties.
Center at (0, 5); r = 9
(x - 0)^2 + (y - 5)^2 = 9^2
To write the equation of a circle in standard form, we use the formula:
(x - h)^2 + (y - k)^2 = r^2
where (h, k) represents the center of the circle and r is the radius. In this case, the center is (0, 5) and the radius is 9. Plugging these values into the formula, we get:
(x - 0)^2 + (y - 5)^2 = 9^2
Simplifying further:
x^2 + (y - 5)^2 = 81
So, the equation of the circle in standard form with the given properties is x^2 + (y - 5)^2 = 81.
To write the equation of a circle in standard form, we need to use the formula:
(x - h)^2 + (y - k)^2 = r^2
where (h, k) represents the center of the circle, and r represents the radius.
Given that the center of the circle is at (0, 5), and the radius is 9, we can substitute these values into the formula:
(x - 0)^2 + (y - 5)^2 = 9^2
Simplifying further:
x^2 + (y - 5)^2 = 81
So, the equation of the circle in standard form, with the given properties, is:
x^2 + (y - 5)^2 = 81