How many grams of O2 would be required to produce 75 grams of SO2
Reaction: 4 FeS + 7 O2 --> 2 Fe2O3 + 4 SO2
how many moles of SO2 in 75g?
It takes 7/4 that many moles of O2
convert that back to grams.
To determine the number of grams of O2 required to produce 75 grams of SO2, we need to use the balanced equation for the reaction:
4 FeS + 7 O2 --> 2 Fe2O3 + 4 SO2
From the equation, we can see that 7 moles of O2 are required to produce 4 moles of SO2.
To find the number of moles of SO2 in 75 grams, we need to use the molar mass of SO2, which is 64.06 g/mol.
Number of moles of SO2 = mass of SO2 / molar mass of SO2
Number of moles of SO2 = 75 g / 64.06 g/mol
Number of moles of SO2 = 1.17 mol
Since the stoichiometry of the reaction tells us that 4 moles of SO2 require 7 moles of O2, we can set up a ratio:
4 mol SO2 / 7 mol O2 = 1.17 mol SO2 / x mol O2
Cross-multiplying and solving for x:
4x = 7 * 1.17
4x = 8.19
x = 8.19 / 4
x = 2.05 mol O2
Now, to find the mass of O2, we can use the molar mass of O2, which is 32.0 g/mol.
Mass of O2 = number of moles of O2 * molar mass of O2
Mass of O2 = 2.05 mol * 32.0 g/mol
Mass of O2 = 65.6 g
Therefore, approximately 65.6 grams of O2 would be required to produce 75 grams of SO2.
To determine the number of grams of O2 required to produce 75 grams of SO2, we need to first understand the stoichiometry of the reaction. The balanced equation tells us that for every 4 moles of FeS reacting, we need 7 moles of O2 to produce 4 moles of SO2.
1. Convert the given mass of SO2 (75 grams) to moles:
- The molar mass of SO2 (sulfur dioxide) is 64.06 g/mol.
- Use the formula: moles = mass / molar mass.
- Calculate: moles of SO2 = 75 g / 64.06 g/mol = 1.171 moles of SO2.
2. Determine the ratio of moles of O2 to moles of SO2:
- From the balanced equation, we know that for every 4 moles of SO2, we need 7 moles of O2.
- Use the ratio: moles of O2 / moles of SO2 = 7 / 4.
3. Calculate the moles of O2 required:
- Use the formula: moles of O2 = moles of SO2 * (moles of O2 / moles of SO2).
- Calculate: moles of O2 = 1.171 moles of SO2 * (7 / 4) = 2.053 moles of O2.
4. Convert moles of O2 to grams:
- The molar mass of O2 (oxygen gas) is 32.00 g/mol.
- Use the formula: mass = moles * molar mass.
- Calculate: mass of O2 = 2.053 moles * 32.00 g/mol = 65.70 grams of O2.
Therefore, 75 grams of SO2 would require approximately 65.70 grams of O2.