Two capacitors of 100 ± 1.4 μF and 80 ± 1.5 μF are connected in parallel. Determine the error of the resultant capacitance in μF and in percentage?
capacitors in parallel add
resultant = (100 + 80) ± (1.4 + 1.5)
% err ... [(1.4 + 1.5) / (100 + 80)] * 100%