Determine the applied force (in newtons, N) required to accelerate a 3.07-kg object rightward with a constant acceleration of 1.27 m/s2 if the force of friction opposing the motion is 16.4 N.
20.3 N
To determine the applied force required to accelerate the object, we need to consider the net force acting on the object.
The net force is given by the equation:
Net force = Applied force - Force of friction
In this case, the force of friction is opposing the motion, so it acts in the opposite direction to the applied force.
Given that the force of friction is 16.4 N, and the object has a mass of 3.07 kg, we can rearrange the equation to solve for the applied force:
Applied force = Net force + Force of friction
Since the object is accelerating rightward, the net force is equal to the product of the mass and acceleration:
Net force = mass × acceleration
Net force = 3.07 kg × 1.27 m/s^2
Net force = 3.9009 N
Now, we can substitute this net force into the equation to find the applied force:
Applied force = 3.9009 N + 16.4 N
Applied force = 20.3009 N
Therefore, the applied force required to accelerate the 3.07-kg object rightward with a constant acceleration of 1.27 m/s^2, considering the force of friction, is approximately 20.301 N.
To determine the applied force required to accelerate an object, we need to consider the force of friction opposing the motion. The applied force should overcome the force of friction to produce the desired acceleration. We can use Newton's second law of motion to help us with this.
Newton's second law states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration:
F_net = m * a
Where:
F_net is the net force (applied force - force of friction)
m is the mass of the object
a is the acceleration of the object
In this case, the force of friction is given as 16.4 N, the mass of the object is 3.07 kg, and the acceleration is 1.27 m/s^2.
We can rearrange the equation to solve for the net force:
F_net = m * a + F_friction
Substituting the given values:
F_net = (3.07 kg) * (1.27 m/s^2) + 16.4 N
F_net = 3.899 N + 16.4 N
F_net = 20.299 N
Therefore, the applied force required to accelerate the 3.07-kg object rightward with a constant acceleration of 1.27 m/s^2, considering the force of friction opposing the motion, is approximately 20.299 N.