Granite has a specific heat of 800 J/g∙°C. What mass of granite is needed to store 150,200 J of heat if the temperature of the granite is to be increased by 15.5°C?
Granite has a specific heat of 800 J/g∙°C. What mass of granite is needed to store 302,400 J of heat if the temperature of the granite is to be increased from 15°C to 45°C?
An ore sample has a mass of 43.02 g. When the sample is added to water in a graduated cylinder, the water rises to 52.5 mL from 44.5 mL. What is the density of this sample?
To find the mass of granite needed to store the given amount of heat, we can use the formula:
Q = m * c * ΔT
where:
Q = heat energy (in Joules)
m = mass of the substance (in grams)
c = specific heat capacity of the substance (in J/g∙°C)
ΔT = change in temperature (in °C)
In this case, we know the values of Q, c, and ΔT, and we need to find the mass (m). Rearranging the formula, we can solve for mass:
m = Q / (c * ΔT)
Now, let's substitute the given values into the formula:
Q = 150,200 J
c = 800 J/g∙°C
ΔT = 15.5°C
m = 150,200 J / (800 J/g∙°C * 15.5°C)
Simplifying the expression:
m = 150,200 J / (12,400 J/g)
Now, perform the division:
m ≈ 12.1 g
Therefore, approximately 12.1 grams of granite is needed to store 150,200 J of heat if the temperature of the granite is to be increased by 15.5°C.