a 10 gram bullet is fired horizontally out of a rifle with a 0.8 m long barrel. The speed of the bullet when it emerges from the barrel is 500 m/s. What was the average force of the exploding gases on the bullet while it traveled through the barrel?

Question

a 10 gram bullet is fired horizontally out of a rifle with a 0.8 m long barrel. The speed of the bullet when it emerges from the barrel is 500 m/s. What was the average force of the exploding gases on the bullet while it traveled through the barrel?

Answer 1

v^2 = 2as

500^2 = 2*a*0.8
now, with a,
F = ma

Answer 2

So would it be 156250 m/s^2

And 1562500 N

Answer 3

watch the units. You need mass in kg

Answer 4

So would it be 156250 m/s^2 and 1562.5 N

Answer 5

To find the average force of the exploding gases on the bullet, we need to use the principle of conservation of momentum.

The principle of conservation of momentum states that the total momentum before an event is equal to the total momentum after the event, provided no external forces are acting.

In this case, the bullet is initially at rest inside the barrel before being fired, so its initial momentum is zero. After being fired, the bullet has a momentum given by its mass (10 grams = 0.01 kg) multiplied by its final velocity (500 m/s).

Now, let's calculate the initial and final momentum of the bullet:

Initial momentum (P_initial) = 0 (since the bullet is initially at rest)
Final momentum (P_final) = mass (m) × final velocity (v)
= 0.01 kg × 500 m/s

Since the total momentum before and after the event must be equal, we have:

P_initial = P_final

0 = 0.01 kg × 500 m/s

To find the average force (F_avg) exerted on the bullet while it traveled through the barrel, we can use the equation:

F_avg = ΔP / Δt

Here, ΔP represents the change in momentum, and Δt represents the time it takes for the bullet to travel through the barrel.

We can rearrange the equation to solve for force:

F_avg = ΔP / Δt = (P_final - P_initial) / Δt

Since the bullet is fired horizontally, the time it takes to travel through the barrel can be calculated using the formula:

Δt = barrel length (L) / final velocity (v)

Substituting the values:

Δt = 0.8 m / 500 m/s

Now that we have the time, we can calculate the average force:

F_avg = (P_final - P_initial) / Δt
= (0.01 kg × 500 m/s - 0) / (0.8 m / 500 m/s)

Simplifying the equation will give us the average force exerted on the bullet.