A Uniform Metre Rule Of Mass 120g Is Pivoted At 60cm Mark. At What Point On Metre Should Mass Of 50g Be Suspended For It To Balance Horizontaly
the 120 g mass acts at the center of the metre rule (50 cm mark)
... 10 cm from the pivot
the 50 g mass needs to be on the other side of the pivot (> 60 cm mark)
120 g * 10 cm = 50 g * ? cm