a 70 kg student stands on top of a 5.0 m platform diving board . how much gravitational potential energy does the student have?
how much work did it take for the student to travel from the ground to the top of the platform diving board?
yes ... but the number of significant figures is iffy
P.E. = m g h
work = P.E.
Pe=(70)(9.8)(5.0)
Pe=3430 J
Is this right
To calculate the gravitational potential energy of the student, we can use the formula:
Gravitational Potential Energy (PE) = mass (m) * gravitational constant (g) * height (h)
Given:
mass (m) = 70 kg
gravitational constant (g) = 9.8 m/s^2
height (h) = 5.0 m
Substituting the given values into the formula:
PE = 70 kg * 9.8 m/s^2 * 5.0 m
PE = 3430 Joules
Therefore, the student has 3430 Joules of gravitational potential energy when standing on top of the 5.0 m platform diving board.
To calculate the work done by the student to travel from the ground to the top of the platform diving board, we can use the formula:
Work (W) = force (F) * distance (d) * cosine(angle)
However, in this case, the force applied by the student is equal to the weight of the student, which can be calculated using:
Force (F) = mass (m) * gravitational constant (g)
Given:
mass (m) = 70 kg
gravitational constant (g) = 9.8 m/s^2
distance (d) = 5.0 m
angle (θ) = 0° (since the student moves vertically)
Substituting the given values into the formula:
Force (F) = 70 kg * 9.8 m/s^2
Force (F) = 686 Newtons
Now, substituting all the values into the work formula:
W = 686 N * 5.0 m * cos(0°)
Since the cosine of 0° is 1:
W = 686 N * 5.0 m * 1
W = 3430 Joules
Therefore, it took 3430 Joules of work for the student to travel from the ground to the top of the platform diving board.