Question

A truck covers 40.0 m in 8.50 s while smoothly slowing down to a final speed of 2.80 m/s.

(a) Find its original speed.
(b) Find its acceleration.

Answer 1

if the original velocity is v, then

a = (2.80-v)/8.5
v*8.5 + 1/2 a*8.5^2 = 40.0
Now solve for v and a.