A student ate a dinner containing 8.0×10⁶j of energy. He wishes to do an equivalent amount of work in a near by gym by lifting a 60kg object . How many times must he raise the object to expand this much energy? Assume that he raises it a distance of 2.0qma each time
work = force * distance.
I have no idea what distance "qma" is
To find out how many times the student must raise the object in order to expend the same amount of energy as the dinner, we need to calculate the work done in each lift.
The work done is given by the equation:
Work = Force × Distance
Given:
Energy of the dinner = 8.0×10⁶ J
Mass of the object (m) = 60 kg
Distance lifted (d) = 2.0 m
To find the force, we use the equation:
Force = Mass × Acceleration due to gravity
Acceleration due to gravity (g) is approximately 9.8 m/s².
Force = 60 kg × 9.8 m/s²
Force = 588 N
Now, we can calculate the work done in each lift:
Work = Force × Distance
Work = 588 N × 2.0 m
Work = 1176 J
To find out how many times the object must be lifted, we divide the total energy of the dinner by the work done in each lift:
Number of lifts = Energy of the dinner / Work done in each lift
Number of lifts = 8.0×10⁶ J / 1176 J
Now, calculating the whole expression:
Number of lifts = (8.0×10⁶ J) / (1176 J)
Number of lifts ≈ 6,803.42
Therefore, the student must raise the object approximately 6,803.42 times to expend the same amount of energy as the dinner.
To find out how many times the student must raise the object to expend the same amount of energy as the dinner, we need to calculate the work done by raising the object once and then divide the total energy consumed by this work.
Let's start by calculating the work done in raising the object:
Work (W) = force (F) × distance (d)
First, we need to calculate the force applied to lift the object. We can use Newton's second law of motion:
Force (F) = mass (m) × acceleration due to gravity (g)
Given:
Mass (m) = 60 kg
Acceleration due to gravity (g) = 9.8 m/s²
Calculating the force:
F = 60 kg × 9.8 m/s²
F = 588 N
Now we can calculate the work done in raising the object once:
Work (W) = force (F) × distance (d)
Work (W) = 588 N × 2.0 m
Work (W) = 1176 J
Now we can find out how many times the student needs to raise the object to expend 8.0×10⁶ J of energy:
Number of times = Total energy consumed / Work done
Total energy consumed = 8.0×10⁶ J
Number of times = (8.0×10⁶ J) / (1176 J)
Number of times ≈ 6790.48
Therefore, the student must raise the object approximately 6791 times to expend the same amount of energy as the dinner.