What is the complete ionic equation of BaCI2(aq) + Na2SO4(aq) > BaSO4(s) + 2NaCI(aq)
Ba^++(aq) + 2CI^-(aq) + 2Na^+(aq) + [SO4]^2-(aq) > BaSO4(s) + 2Na^+(aq)+ 2CI^-(aq)
well
Cl- has one extra electron
Ba++ is missing 2 electrons (so you need 2 Cl- ions for every Ba++)
Na+ is missing one electron
SO4-- Has 2 extra electrons
Oh, we've got ourselves a chemical equation here! Let me clown around with it and provide you with a bit of humor along the way:
BaCI2(aq) + Na2SO4(aq) → BaSO4(s) + 2NaCI(aq)
Now, let's break this down into its ionic components:
Barium chloride (BaCI2) will dissociate into Ba²⁺ and 2CI⁻ ions in water. Meanwhile, sodium sulfate (Na2SO4) will split into 2Na⁺ and SO₄²⁻ ions. The result of this amusing chemistry show is as follows:
Ba²⁺(aq) + 2CI⁻(aq) + 2Na⁺(aq) + SO₄²⁻(aq) → BaSO4(s) + 2Na⁺(aq) + 2CI⁻(aq)
But hold your laughter, because in complete ionic equations, we have to cancel out any spectator ions that appear on both sides of the equation. In this case, the fabulous Na⁺ and CI⁻ ions are playing the role of spectators. So, they're out of the equation! Let's give them a round of applause:
Ba²⁺(aq) + SO₄²⁻(aq) → BaSO4(s)
And there you have it! The complete ionic equation with a twist of humor. Keep calm and chemistry on!
To write the complete ionic equation of the given chemical reaction, we need to break down all the ionic compounds into their constituent ions (if they are soluble), including the aqueous (aq) compounds and the solid (s) compound. Here's how you can do it:
Step 1: Write the balanced molecular equation for the reaction.
The given balanced molecular equation is:
BaCl2(aq) + Na2SO4(aq) → BaSO4(s) + 2NaCl(aq)
Step 2: Identify the soluble compounds.
In this equation, BaCl2 and Na2SO4 are soluble compounds, while BaSO4 and NaCl are insoluble and soluble compounds, respectively.
Step 3: Write the dissociation of soluble compounds.
BaCl2(aq) can dissociate into Ba2+(aq) + 2Cl-(aq)
Na2SO4(aq) can dissociate into 2Na+(aq) + SO4^2-(aq)
BaSO4(s) remains as BaSO4(s) in the equation (as it is already a solid).
2NaCl(aq) remains as 2NaCl(aq) in the equation (as it is already aqueous).
Step 4: Write the complete ionic equation.
Now, combining the dissociated ions from step 3, we can form the complete ionic equation:
Ba2+(aq) + 2Cl-(aq) + 2Na+(aq) + SO4^2-(aq) → BaSO4(s) + 2Na+(aq) + 2Cl-(aq)
That's the complete ionic equation for the given reaction: Ba2+(aq) + 2Cl-(aq) + 2Na+(aq) + SO4^2-(aq) → BaSO4(s) + 2Na+(aq) + 2Cl-(aq).