Two eight-grade classes are selling raffle tickets to raise money
•one class is selling tickets for $2.50 each and had already raised $350
•the other class is selling tickets for $3.00 each and has already raised $225.
Which equation can be used to find t,the number of tickets each class needs to sell so that the total amount raised is the same for both classes
To find the equation that represents the number of tickets each class needs to sell, we can set up a proportion based on the total amount raised.
Let's assume that the first class needs to sell "x" tickets, and the second class needs to sell "y" tickets. The total amount raised by the first class is given as $350, and the total amount raised by the second class is given as $225.
Using the given information, we can set up the following proportion:
(1st class sales) / (2nd class sales) = (1st class amount raised) / (2nd class amount raised)
x / y = 350 / 225
To make the equation more general, we can express the cost per ticket for the first class as $2.50 and the cost per ticket for the second class as $3.00. We can then modify the equation to account for these costs:
(1st class sales) * (1st class cost per ticket) / (2nd class sales) * (2nd class cost per ticket) = (1st class amount raised) / (2nd class amount raised)
x * $2.50 / y * $3.00 = 350 / 225
Simplifying the equation:
2.5x / 3y = 350 / 225
Cross-multiplying:
2.5x * 225 = 350 * 3y
Simplifying further:
562.5x = 1050y
Therefore, the equation that can be used to find the number of tickets each class needs to sell, "t," so that the total amount raised is the same for both classes is:
562.5x = 1050y