Find the equation of the tangent to the curve y = 2 - sqrt(x) perpendicular to the straight line y + 4x - 4 = 0. Can you guys help with finding the answer with steps?
You want a line with slope 1/4
dy/dx = -1/(2√x)
so,
-1/(2√x) = 1/4
2√x = -4
Sorry. No such line. I suspect a typo.