A GLASS CUP OF ORANGE JUICE IS FOUND TO HAVE A POH OF 11.40. CALCULATE THE CONCENTRATION OF THE HYDROGEN ION IN THE JUICE.
THE ANSWER'S
To calculate the concentration of the hydrogen ion (H+) in the juice, we first need to determine the concentration of the hydroxide ion (OH-) using the pOH value given.
pOH is related to the hydroxide ion concentration by the equation:
pOH = -log[OH-]
Given: pOH = 11.40
We can rearrange the equation to solve for [OH-]:
log[OH-] = -pOH
Now, we can calculate the hydroxide ion concentration:
[OH-] = 10^(-pOH)
[OH-] = 10^(-11.40)
[OH-] ≈ 3.981 x 10^(-12) M
Since pure water is neutral and has equal concentrations of H+ and OH- ions, we can assume that the concentration of the hydrogen ion (H+) is the same as the OH- concentration:
[H+] = [OH-] ≈ 3.981 x 10^(-12) M
Therefore, the concentration of the hydrogen ion in the orange juice is approximately 3.981 x 10^(-12) M.
To calculate the concentration of the hydrogen ion in the juice, we can use the relation between pOH and pH. The pOH and pH are related by the equation:
pOH + pH = 14
Given that the pOH of the orange juice is 11.40, we can calculate the pH as follows:
pOH + pH = 14
11.40 + pH = 14
To isolate pH, we can subtract 11.40 from both sides:
pH = 14 - 11.40
pH = 2.60
Now that we have the pH value, we can calculate the concentration of the hydrogen ion using the relation:
pH = -log[H+]
Rearranging the equation to isolate [H+], we get:
[H+] = 10^(-pH)
Plugging in the value of pH, we have:
[H+] = 10^(-2.60)
[H+] = 0.00398 M
Therefore, the concentration of the hydrogen ion in the orange juice is 0.00398 M.
Solve the two following equations.
pH + pOH = pK2 = 14. Knowing pOH and pKw you can calculate pH. Then pH = -log (H^+) when get you the hydrogen ion.