rewrite (7+4)3 using the distributive property
f 7+3x4+3 H 7x3+4x3
g 3x7x3x4 j(7+3)+(4+3)
To rewrite (7+4)3 using the distributive property, we need to distribute the 3 to both the 7 and the 4.
So, we multiply the 3 by both the 7 and the 4 separately:
(7+4)3 = 7*3 + 4*3
Simplifying this expression, we get:
(7+4)3 = 21 + 12
Therefore, the correct answer is: H) 7x3+4x3.