The orbital hybridization on the carbon atom in S CN - is
a) sp.
b) sp2.
c) sp3.
d) sp3d2.
a
https://brainly.in/question/12135419
To determine the orbital hybridization on the carbon atom in the CN- molecule, we need to consider the molecular geometry and the number of electron domains (bonding and lone pairs) around the carbon atom.
In CN-, carbon is the central atom bonded to a nitrogen atom and has a negative charge. The nitrogen atom has a triple bond with the carbon atom, resulting in a linear molecular geometry.
Based on the molecular geometry and the number of electron domains, we can determine the hybridization as follows:
- A linear geometry corresponds to sp hybridization.
- A trigonal planar geometry corresponds to sp2 hybridization.
- A tetrahedral geometry corresponds to sp3 hybridization.
- A trigonal bipyramidal geometry corresponds to sp3d hybridization.
Since the CN- molecule has a linear geometry around the carbon atom, the hybridization on the carbon atom is sp.
Therefore, the correct answer is (a) sp.