if a calorimeter has a total heat capacity of 11j/c how much heat was gained by the calorimeter for a temperature increase of 5.8c
c= degree celsius
heat gained = q = Ccal x delta T = 11 J/c x 5.8 C = ?
so 63.8 J?
I wouldn't go three significant digits...
Bob P is right. I would round that to 64. The 11 and 5.8 limit the answer to 2 digits.
To calculate the heat gained by the calorimeter, you can use the formula:
Q = C * ΔT
Where:
Q is the heat gained (in Joules)
C is the heat capacity of the calorimeter (in Joules per degree Celsius)
ΔT is the change in temperature (in degrees Celsius)
In this case, the heat capacity of the calorimeter is given as 11 J/°C, and the change in temperature is 5.8 °C.
Now, substitute these values into the formula to solve for Q:
Q = 11 J/°C * 5.8 °C
Multiplying the values together:
Q = 63.8 J
Therefore, the calorimeter gained 63.8 Joules of heat for a temperature increase of 5.8 degrees Celsius.