What is the initial electric potential energy of an electron leaving a 200-volt battery if the charge of an electron is 1.602×10−19 coulombs?
8.01×10−20 joules
3.204×10−19 joules
8.01×10−22 joules
3.204×10−17 joules
it's actually D. 3.204 x 10^-17 joules
did you get any answers
To find the initial electric potential energy of an electron leaving a 200-volt battery, we can use the formula:
Electric Potential Energy = Charge × Voltage
In this case, the charge of an electron is given as 1.602×10−19 coulombs, and the voltage of the battery is 200 volts.
Substituting these values into the formula, we get:
Electric Potential Energy = (1.602×10−19 C) × (200 V)
Calculating this expression, we find:
Electric Potential Energy = 3.204×10−17 joules
Therefore, the initial electric potential energy of the electron leaving the 200-volt battery is 3.204×10−17 joules.