A biker first accelerates from 0.0 m/s to 6.0 m/s in 6 s, then continues at this speed for 5 s. What is the total distance traveled by the biker.؟
{[(0.0 m/s + 6.0 m/s) / 2] * 6 s} + [(6.0 m/s) * 5 s]
To find the total distance traveled by the biker, you need to calculate the distance covered during acceleration and the distance covered during the constant speed phase, and then add these two distances together.
1. Distance covered during acceleration:
During acceleration, the biker's initial velocity is 0.0 m/s, and the final velocity is 6.0 m/s. The time taken to accelerate is 6 seconds. You can use the formula:
distance = (final velocity - initial velocity) * time
distance = (6.0 m/s - 0.0 m/s) * 6 s
distance = 36.0 meters
So, the distance covered during acceleration is 36.0 meters.
2. Distance covered during constant speed:
The biker continues at a speed of 6.0 m/s for 5 seconds. The formula to calculate distance is:
distance = velocity * time
distance = 6.0 m/s * 5 s
distance = 30.0 meters
Therefore, the distance covered during the constant speed phase is 30.0 meters.
3. Total distance traveled:
To find the total distance, you simply add the distance covered during acceleration and the distance covered during the constant speed phase:
total distance = distance during acceleration + distance during constant speed
total distance = 36.0 meters + 30.0 meters
total distance = 66.0 meters
Hence, the total distance traveled by the biker is 66.0 meters.