if you had a cup full of methanol and a pool full of methanol would they have the same mass or different mass? pls explain why thank u :)
To determine if a cup full of methanol and a pool full of methanol would have the same or different mass, we need to consider the properties of methanol and how mass is measured.
Methanol is a liquid with a known density, which is the ratio of mass to volume. The density of methanol is approximately 0.791 grams per milliliter (g/mL).
In the case of the cup filled with methanol, we need to know the volume of the cup to calculate the mass. Let's assume the cup has a volume of 250 milliliters (mL) (standard cup size). To find the mass, we multiply the volume by the density:
Mass = Volume × Density = 250 mL × 0.791 g/mL = 197.75 grams
So, the cup full of methanol would have a mass of approximately 197.75 grams.
Now, let's consider the pool full of methanol. Pools come in various sizes, so to make the calculations easier, let's imagine a pool with a volume of 10,000 liters (L). To convert liters to milliliters, we multiply by 1,000:
Volume of pool = 10,000 L × 1,000 mL/L = 10,000,000 mL
To calculate the mass of the pool full of methanol, we again multiply the volume by the density:
Mass = Volume × Density = 10,000,000 mL × 0.791 g/mL = 7,910,000 grams
So, the pool full of methanol would have a mass of approximately 7,910,000 grams, which is significantly greater than the mass of the cup full of methanol.
In conclusion, a cup full of methanol and a pool full of methanol would have different masses due to the difference in volume. The larger the volume, the greater the mass. This is because mass is directly proportional to the volume of a substance when density remains constant.