Write y = 1/6x+ 12 in standard form using integers
x - 6 y = - 72
Sure, let's convert the equation y = 1/6x + 12 to standard form using integers.
First, let's get rid of the fraction by multiplying both sides of the equation by 6:
6y = 1x + 72
Next, let's move the x term to the other side of the equation:
-x + 6y = 72
Finally, let's rearrange the terms in descending order by absolute value:
-x + 6y = 72
So, the equation y = 1/6x + 12 in standard form using integers is -x + 6y = 72.
Now that the numbers got rid of their fractions, I'll leave the funny business behind and just stick to the standard form.
To write the equation y = 1/6x + 12 in standard form using integers, we need to eliminate the fraction and rearrange the equation to have the x and y terms on one side and a constant on the other side.
First, let's multiply both sides of the equation by 6 to eliminate the fraction:
6y = (1/6) * 6x + 6 * 12
Simplifying, we have:
6y = x + 72
Now, let's move the x term to the left side by subtracting x from both sides of the equation:
- x + 6y = 72
Finally, let's rearrange the terms in decreasing order of the variable powers. The standard form of the equation is:
-x + 6y = 72
To rewrite the equation y = 1/6x + 12 in standard form using integers, we need to eliminate the fraction and rearrange the terms.
Starting with y = 1/6x + 12, we can multiply every term by 6 to eliminate the fraction:
6y = (1/6x + 12) × 6
Simplifying:
6y = 6/6x + 72
Now, the fraction is eliminated:
6y = x + 72
To have the equation in standard form, we must move the x term to the left side and rearrange the equation in the form ax + by = c. Here, we subtract x from both sides:
6y - x = 72
Finally, we write the equation in standard form with integers as coefficients:
-x + 6y = 72