A basket tied to a rope has mass of 4.23kg. what is the force exerted by the rope to the basket if it is being pulled upward with an acceleration of 1.25 m/s2?
To determine the force exerted by the rope on the basket, we need to use Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration.
Given:
Mass of the basket (m) = 4.23 kg
Acceleration (a) = 1.25 m/s²
The formula to calculate force (F) is:
F = m * a
Substituting the given values:
F = 4.23 kg * 1.25 m/s²
Simplifying the equation:
F = 5.2875 N
Therefore, the force exerted by the rope on the basket is approximately 5.29 N (rounded to two decimal places).
To find the force exerted by the rope on the basket, we can use Newton's second law of motion, which states that the force (F) acting on an object is equal to the mass (m) of the object multiplied by its acceleration (a).
Given:
Mass of the basket (m) = 4.23 kg
Acceleration (a) = 1.25 m/s^2
Using the formula F = m * a, we can substitute the given values into the equation:
F = 4.23 kg * 1.25 m/s^2
Calculating the multiplication, we find:
F = 5.2875 N
So, the force exerted by the rope on the basket is 5.2875 N.