A light bulb has the rating 200W 220V.
1. Find the peak value of current
2. If the supply voltage is 220V, then find power consumed by the bulb
To find the answers to your questions, we need to use some basic formulas related to electrical power and voltage.
1. Finding the peak value of current:
- The rating of the light bulb is given as 200W and 220V.
- We know that power (P) is equal to the product of voltage (V) and current (I): P = V * I.
- Rearranging the formula, we get I = P / V.
- Plugging in the given values, we have I = 200W / 220V.
- Here, W stands for watts and V for voltage.
- Therefore, the peak value of current (I) is 0.909 Amperes (A) (rounded to three decimal places).
2. Finding the power consumed by the bulb:
- The supply voltage is given as 220V.
- We're required to find the power consumed by the bulb.
- We already know that P = V * I, where P is power, V is voltage, and I is current.
- Here, we can use either the peak value of current we calculated earlier (0.909A) or calculate the current again using the formula I = P / V.
- Plugging in the given values: P = 220V * 0.909A.
- The voltage cancels out, and we get P = 200W (rounded to the nearest whole number).
- Therefore, the power consumed by the bulb is 200W.