Questions LLC
Login
or
Sign Up
Ask a New Question
Questions
Mathematics
If tanø = u/v, 0°<ø<290, find cosø
1 answer
cosø = v / √(u^2 + v^2)
You can
ask a new question
or
answer this question
.
Related Questions
Given that, tanØ=5/12,
Using trigonometric ratio, please solve ; (1). SinØ (2). SinØ + Cos Ø (3). (Sin^2 Ø / Cos Ø)/(Sin^2
sinØ (1+ tanØ) + cosØ(1+ cotØ) = (secØ + cosecØ)
Secø + tanø=x
Then find the value of secø
As the answer to:
(tanØ * cosØ/ sinØ) + cotØ * sinØ * tanØ* cscØ I got 2, is that correct?
Prove the following:
1/(tanØ - secØ ) + 1/(tanØ + secØ) = -2tanØ (1 - sinØ)/(1 + sinØ) = sec^2Ø - 2secØtanØ + tan^2Ø
Prove that:Tanø+sinø/tanø-sinø=secø+1/secø-1
Tanø(secø+2)
if cos ø=1/2then find the value of 2secø/1+tanø
For an angle Ø in standard position, sin = √2/2 and tanØ = -1 can the value be 225
Verify the identity , justify each step
tanØ+cotØ = 1/ sin Ø cosØ