3x = ±π/6+2kπ/3, ±5π/6+2kπ/3
pick values of k that put x in [-π/2,π/2]
I am confused on how to do this.
come on.
If k=1, than the values are
π/6 + 2π/3 = 5π/6
-π/6 + 2π/3 = π/2
5π/6 + 2π/3 = 3π/2
-5π/6 + 2π/3 = -π/6
So with k=1 you get the values π/2, -π/6
The next values will be those + or - 2π/3, so check to see which ones lie in the desired interval.