A car of mass 500kg is travelling along aflat road accelerates at 0.2m/s after its engine provides a forward force of 300N
A car of mass 500kg is travelling along flat aroed accelerated 0.2 after its engine providesafirward force of 300N what is the drag force
500 kg * 0.2 m/s^2 = 100 N
So, 300-100 = 200N was dissipated by drag
To find the acceleration of the car, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration.
Given:
Mass of the car (m) = 500 kg
Force (F) = 300 N
We know that force (F) = mass (m) × acceleration (a).
Rearranging the formula, we get:
Acceleration (a) = Force (F) / Mass (m)
Substituting the given values, we have:
Acceleration (a) = 300 N / 500 kg
Simplifying:
Acceleration (a) = 0.6 m/s^2
Therefore, the car accelerates at a rate of 0.6 m/s^2.
To find the acceleration of the car, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration. The formula for this law is:
F = ma
Where:
F is the net force applied on the object,
m is the mass of the object, and
a is the acceleration.
In this case, we have the force provided by the car's engine (F = 300 N) and the mass of the car (m = 500 kg). Therefore, we need to rearrange the formula and solve for acceleration (a):
a = F / m
Plugging in the given values:
a = 300 N / 500 kg
a = 0.6 m/s²
Therefore, the car's acceleration is 0.6 m/s².