While running at 13 mph directly toward
Patrick, Lisa passes a basketball to him.
Patrick is stationary when he receives the
ball, which is moving at a speed of 49 mph.
How fast did Lisa throw the ball?
Answer in units of mph.
ok so this is simple but its worded weird. Basically subtract the ball's speed by Lisa's speed. (49-13)=39.
You're answer is 39 mph
Sorry i meant 36
To find how fast Lisa threw the ball, we need to determine the velocity of the ball relative to Patrick.
Given:
- Lisa's speed (velocity) = 13 mph
- Ball's speed (velocity) = 49 mph
- Patrick's speed (velocity) = 0 mph (since he is stationary)
The velocity of the ball relative to Patrick can be calculated by subtracting Patrick's speed from the velocity of the ball:
Relative velocity = Ball's velocity - Patrick's velocity
Relative velocity = 49 mph - 0 mph
Relative velocity = 49 mph
Therefore, the ball's speed relative to Patrick is 49 mph. Hence, Lisa threw the ball at a speed of 49 mph.
To determine how fast Lisa threw the ball, we can use the concept of relative velocity. The relative velocity is the difference in velocities between two objects when observed from a certain reference frame.
In this scenario, we have two objects: Lisa (the thrower) and the basketball. Lisa is running at 13 mph towards Patrick, and she passes the basketball to him. Patrick is stationary when he receives the ball, which is moving at a speed of 49 mph.
To find the speed at which Lisa threw the ball, we need to calculate the relative velocity between Lisa (the thrower) and the basketball.
Relative velocity = Velocity of the basketball - Velocity of Lisa
Since the basketball is moving towards Patrick, its velocity is positive (+49 mph), and Lisa is moving towards Patrick as well, so her velocity is also positive (+13 mph).
Relative velocity = 49 mph - 13 mph = 36 mph
Therefore, Lisa threw the ball at a speed of 36 mph.