the floor plan of a room has a scale of 2.5in . : 35ft. in the drawing the length of the room is 8 in . and the whole width of the room is 6in, what is the perimeter of the actual room ?
To find the perimeter of the actual room, we first need to calculate the length and width of the room in feet based on the given scale.
Given:
Scale: 2.5in. : 35ft.
Length on drawing: 8in.
Width on drawing: 6in.
Step 1: Calculate the actual length of the room in feet:
Length on drawing (inches) / Scale (inches:feet) = Length of room (feet)
8in. / 2.5in. : 35ft. = 8in. / 2.5in. * 35ft.
8in. / 2.5in. * 35ft. = 112ft.
Therefore, the actual length of the room is 112ft.
Step 2: Calculate the actual width of the room in feet:
Width on drawing (inches) / Scale (inches:feet) = Width of room (feet)
6in. / 2.5in. : 35ft. = 6in. / 2.5in. * 35ft.
6in. / 2.5in. * 35ft. = 84ft.
Therefore, the actual width of the room is 84ft.
Step 3: Calculate the perimeter of the actual room:
Perimeter = 2 * (Length + Width)
Perimeter = 2 * (112ft. + 84ft.)
Perimeter = 2 * 196ft.
Perimeter = 392ft.
Therefore, the perimeter of the actual room is 392ft.
The scale is 35*12/2.5 = 168:1
So the room is 6*168 by 8*168 = 1354752 in^2 = 9408 ft^2