What is the velocity of a jet plane that travels 200 meters east in 10 seconds?
physics, not phasics
200m/10s = 20 m/s east
always pay attention to the units involved.
To find the velocity of the jet plane, we need to divide the distance traveled by the time taken.
Given:
Distance = 200 meters
Time = 10 seconds
Velocity = Distance / Time
Velocity = 200 meters / 10 seconds
Velocity = 20 meters per second
Therefore, the velocity of the jet plane is 20 meters per second.
To find the velocity of a jet plane, we need to divide the displacement by the time taken.
In this case, the displacement is 200 meters east, which means the plane's motion is in the positive x-direction.
The time taken is 10 seconds.
So, the velocity (v) can be calculated using the formula:
v = displacement / time
v = 200 meters / 10 seconds
v = 20 meters/second
Therefore, the velocity of the jet plane is 20 meters per second (20 m/s) in the east direction.