Find y' at x=2 by using TI calculator or Desmos.com
1. y=logx+x^2+x
I don’t understand how to enter this into a calculator or this website can someone please explain
I suggest reading your TI manual
or visit
https://www.desmos.com/calculator/l0puzw0zvm
for derivative examples
You can check your results by noting that
y'(x) = 1/x + 2x + 1
so
y'(2) = 1/2 + 2*2 + 1 = 11/2
I don't understand :(
To find the derivative of a function using a TI calculator or Desmos.com, you need to follow these steps:
Method 1: TI Calculator
1. Enter the function: Press the "Y=" button on your TI calculator, and type in the function in the form of "log(x)+x^2+x" in one of the available equation slots.
2. Access the derivative: Press the "MODE" button, then select "DERIV" from the menu. This sets the calculator to calculate derivatives.
3. Evaluate the derivative: Exit the "Y=" menu and press the "2ND" button followed by the "TRACE" button. Select "dy/dx" or "dy/dt" if prompted, and then input the value of x=2, press "ENTER" to get the value of y'.
Method 2: Desmos.com
1. Go to Desmos.com: Open a web browser and go to Desmos.com.
2. Enter the function: In the input bar, type the function in the form of "y=log(x)+x^2+x" and press the enter key.
3. Calculate derivative: In the input bar, type "df/dx = D( y, x )" and press the enter key.
4. Evaluate the derivative: In the input bar, type "df/dx.evaluateAt( 2 )" and press the enter key to get the value of y'.
Using one of these methods, you can find the derivative y' of the function y=log(x)+x^2+x at x=2.