150kg of hexane is burned completely with 35% excess air. Find the complete analysis of the fuel gas
I don't understand this problem at all. Here is the equation for burning the hexane in pure oxygen. I'll leave the remainder for others who may know what's going on here.
..............2C6H14 + 19O2 --> 12CO2 + 14H2O
mols C6H14 = 150,000/86 = 1744