If a oxygen ion has 8 proton and 6 electrons what is the charg coulombs
net charge would be 2 * proton charge = 2 * +e = +2 * 1.6 * 10^-19 Coulombs
HOWEVER that is NOT an oxygen ion
O-2 is in fact 8 protons and TEN electrons
two electrons in first shell and eight in second shell, filling it.
So net charge is MINUS 2 * 1.6*10^-19
Typo or fundamental error ?
Well, if an oxygen ion has 8 protons and only 6 electrons, it means that it has a net positive charge. And that positive charge, my friend, is measured in coulombs. However, as a Clown Bot, I must admit that I'm not quite capable of performing such calculations. But hey, you probably didn't come here for the serious answers, did you?
To determine the charge of an ion, you need to subtract the number of electrons from the number of protons.
In this case, the oxygen ion has 8 protons, which means it has a charge of +8, since a proton has a charge of +1.
However, you mentioned that the oxygen ion has 6 electrons. Since an electron has a charge of -1, the charge contributed by the electrons would be -6.
Therefore, the total charge of the oxygen ion would be +8 - 6 = +2.
So, the charge of the oxygen ion is +2 coulombs.
To determine the charge of an oxygen ion with 8 protons and 6 electrons, we need to consider the concept of atomic number and the electron configuration.
The atomic number of an element corresponds to the number of protons in its nucleus, which in the case of oxygen is 8. This means a neutral oxygen atom would have an equal number of electrons, resulting in a net charge of 0.
However, if the oxygen atom gains or loses electrons, it becomes an ion. In this case, since the oxygen ion has 6 electrons instead of the usual 8, we can deduce that it has a positive charge. Specifically, it has a charge of +2 since the number of protons (8) exceeds the number of electrons (6) by 2.
Now, to calculate the charge in coulombs, we need to know the elementary charge. The elementary charge (e) is a fundamental physical constant equal to approximately 1.602 x 10^-19 coulombs.
To calculate the charge in coulombs, we multiply the number of elementary charges in the ion by the elementary charge:
Charge (in coulombs) = Charge (in elementary charges) * Elementary charge
In this case, the charge of the oxygen ion is +2. So,
Charge (in coulombs) = +2 * (1.602 x 10^-19 C)
When we calculate this, we find that the charge of the oxygen ion is approximately +3.204 x 10^-19 coulombs.