the mass of a sheet of metal varies jointly with its area and its thickness a sheet of metal of area 250 cm square and thickness 1 mm has a mass of 200 g find the formula which connect the mass,the area and the thickness

m = ka/t

so, using your numbers,
200g = k(250 cm^2)/(1 mm) = k * 2500 cm
so k = 200g/2500cm = 2/25 g/cm
m = .08a/t

Google "mass,the area and the thickness formula" and read. carefully.

I need an answer

M .08a/t

Joint variation

The mass of a sheet of metal varies jointly with its area and its thickness a sheet of metal of area 259cm^2 and thickness 1mm has a mass of 200gk

That's good

Blah blah blah

I know you

To find the formula that connects the mass, area, and thickness, we need to understand the concept of joint variation.

In joint variation, when two variables (in this case, area and thickness) are related proportionally to a third variable (mass), it can be expressed using the formula:

mass = k * area * thickness

Where:
- mass is the mass of the sheet of metal,
- area is the area of the sheet of metal,
- thickness is the thickness of the sheet of metal, and
- k is the constant of variation.

Now, to determine the value of the constant of variation (k), we can use the given information.

Given:
- Area = 250 cm²,
- Thickness = 1 mm,
- Mass = 200 g.

Substituting these values into the formula, we have:

200 = k * 250 * 1

Simplifying further:

200 = 250k

Next, we can solve for k by dividing both sides of the equation by 250:

k = 200 / 250
k = 0.8

So, the formula that connects the mass (m), area (A), and thickness (T) is:

mass = 0.8 * area * thickness