a solid weighs 40 newton when totally immersed in a liquid of relative density 0.8. calculate the weight of the solid when immersed in water
50 Newton's
To calculate the weight of the solid when immersed in water, we need to consider the relative density of water, which is 1.
The weight of a body immersed in a fluid can be calculated using the formula:
Weight in fluid = Weight in air - Buoyant Force
The buoyant force can be determined by the formula:
Buoyant Force = Volume of the solid × Density of fluid × Acceleration due to gravity
First, let's calculate the volume of the solid:
Volume = Weight in air / Density of fluid
Volume = 40 N / 0.8 = 50 m³
Now, let's calculate the weight of the solid when immersed in water:
Weight in water = Weight in air - Buoyant Force
Buoyant Force = Volume of the solid × Density of water × Acceleration due to gravity
Buoyant Force = 50 m³ × 1000 kg/m³ × 9.8 m/s² = 49000 N
Weight in water = 40 N - 49000 N = -48960 N
Since the weight in water is negative, it means the buoyant force is greater than the weight of the solid in air. Therefore, the weight of the solid when immersed in water is -48960 N.
To calculate the weight of the solid when immersed in water, we need to use the concept of relative density.
Relative density (also known as specific gravity) is defined as the ratio of the density of a substance to the density of a reference substance. In this case, the reference substance is water, which has a relative density of 1.
The relative density of the liquid the solid is immersed in is given as 0.8. This means that the liquid is 0.8 times as dense as water.
Given that the solid weighs 40 Newton when immersed in the liquid, we can use the following formula to calculate the weight of the solid when immersed in water:
Weight in water = Weight in liquid × Relative density of liquid
Weight in water = 40 Newton × 0.8
Weight in water = 32 Newton
Therefore, the weight of the solid when immersed in water is 32 Newton.