A rocket expels gas at the rate of 0,2kg/s. if the force produced by the rocket is 15N, what is the velocity with which the gas is expelled.
F*time=m*v
force= mass/time * velocty
velocity= 15N/ (.2kg/sec)= 16/.2 m/s
1 N = 1 kg⋅m/s^2
15 kg⋅m/s^2 / 0.2 kg/s = 75 m/s
To find the velocity with which the gas is expelled, we can use Newton's Second Law of Motion, which states that the force exerted on an object is equal to the mass of the object multiplied by its acceleration (F = m * a).
In this case, the force (F) is 15N and the mass (m) is 0.2kg/s (since the rocket expels 0.2kg of gas per second). We need to find the acceleration (a).
Rearranging the equation, we have a = F / m. Substituting the known values, we get:
a = 15N / 0.2kg/s
Now, divide the force by the mass flow rate to find the acceleration:
a = 75 m/s^2
The acceleration represents the rate at which the velocity changes, so the velocity of the gas being expelled is continuously increasing by 75 m/s for every second. Therefore, the velocity with which the gas is expelled is 75 m/s.