angle of depression of a car from the top of a building 50cm high is 55 degrees .find the distance of the car from the foot of the building.
height of building = per = 50 cm
angle of depression = angle = 55o
distance of the car from the foot of the building = base = ?
solution :
by applying trigonometric identities,
tanα = per/base
tan55 = 50/distance
distance = 50/tan55
distance = 35.211
tangent55= 50cm/ distance
solve for distance.
Now really, a building that is 50 cm high. Is the building for cats?
Thank you
In my own solving it is not giving me this answer
The answer is 35m
I got it thanks
To find the distance of the car from the foot of the building, we can use trigonometric ratios. Specifically, we can use the tangent function.
Let's denote the distance from the foot of the building to the car as "x".
We have the angle of depression (from the top of the building) as 55 degrees. This means that the angle between the horizontal line (ground) and the line connecting the top of the building to the car is also 55 degrees.
We can use the tangent function, which is defined as the ratio of the length of the opposite side to the length of the adjacent side. In this case, the opposite side is the height of the building (50 cm) and the adjacent side is the distance from the foot of the building to the car (x).
So we have:
tan(55 degrees) = opposite / adjacent
tan(55 degrees) = 50 cm / x
To find x, we rearrange the equation:
x = 50 cm / tan(55 degrees)
Now we can calculate the value of x using a calculator:
x ≈ 50 cm / 1.428
x ≈ 35 cm
Therefore, the distance of the car from the foot of the building is approximately 35 cm.